log[5](x+1)-log[5](x-1)=2

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Solution for log[5](x+1)-log[5](x-1)=2 equation: 


Simplifying
log[5](x + 1) + -1log[5](x + -1) = 2

Reorder the terms:
glo * 5(1 + x) + -1log[5](x + -1) = 2

Reorder the terms for easier multiplication:
5glo(1 + x) + -1log[5](x + -1) = 2
(1 * 5glo + x * 5glo) + -1log[5](x + -1) = 2
(5glo + 5glox) + -1log[5](x + -1) = 2

Reorder the terms:
5glo + 5glox + -1glo * 5(-1 + x) = 2

Reorder the terms for easier multiplication:
5glo + 5glox + -1 * 5glo(-1 + x) = 2

Multiply -1 * 5
5glo + 5glox + -5glo(-1 + x) = 2
5glo + 5glox + (-1 * -5glo + x * -5glo) = 2
5glo + 5glox + (5glo + -5glox) = 2

Reorder the terms:
5glo + 5glo + 5glox + -5glox = 2

Combine like terms: 5glo + 5glo = 10glo
10glo + 5glox + -5glox = 2

Combine like terms: 5glox + -5glox = 0
10glo + 0 = 2
10glo = 2

Solving
10glo = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Divide each side by '10lo'.
g = 0.2l-1o-1

Simplifying
g = 0.2l-1o-1

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